BaerCoil® thread inserts – nominal length determination
Screw strength classes | ||||||||
---|---|---|---|---|---|---|---|---|
Tensile strength of the material | 4,6 | 5,6 | 6,6 | 6,9 | 9,8 | 10,9 | 12,9 | 14,9 |
< 100 N/mm² | 1,5 D | 1,5 D | 2,0 D | 2,5 D | 3,0 D | |||
100 - 150 N/mm² | 1,5 D | 1,5 D | 2,0 D | 2,0 D | 2,5 D | 2,5 D | 2,5 D | 3,0 D |
150 - 200 N/mm² | 1,0 D | 1,5 D | 1,5 D | 1,5 D | 2,0 D | 2,0 D | 2,5 D | 2,5 D |
200 - 250 N/mm² | 1,0 D | 1,0 D | 1,5 D | 1,5 D | 1,5 D | 2,0 D | 2,5 D | 2,5 D |
250 - 300 N/mm² | 1,0 D | 1,0 D | 1,0 D | 1,0 D | 1,5 D | 1,5 D | 2,0 D | 2,0 D |
300 - 350 N/mm² | 1,0 D | 1,0 D | 1,0 D | 1,0 D | 1,5 D | 1,5 D | 1,5 D | 2,0 D |
350 - 400 N/mm² | 1,0 D | 1,0 D | 1,0 D | 1,0 D | 1,0 D | 1,5 D | 1,5 D | 1,5 D |
> 400 N/mm² | 1,0 D | 1,0 D | 1,0 D | 1,0 D | 1,0 D | 1,5 D | 1,5 D | 1,5 D |
Valid at room temperature for materials (e.g. aluminum) with a ratio of (shear stress) / (tensile stress) = 0.6 to 0.7.
The calculation was based on the fact that the screw should be the weaker link in the screw connection.
Thread length: 1.5 D = 1.5 times nominal diameter
Data are without guarantee - In case of doubt, tests should be carried out.
Determination of the minimum wall thickness
d = Nominal diameter
D = Outside diameter of the holding thread
R = Residual wall thickness
R (min) = 0.375 x D
G (min) = 1.75 x D
The minimum wall thicknesses can only be determined with the aid of the respective characteristic values.
The guide formulas given refer to cast, aluminum or wrought alloys and
a length of the Baercoil thread insert of 1.5 D.